Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
4. Rational Expressions
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Exercise 60 Page 533

Set up an equation and apply the definition of a logarithm.

3/4

Practice makes perfect
To evaluate the given logarithm, we will start by writing a logarithmic equation. log_(16) 8=x In order to solve this equation, we can rewrite it as an exponential equation by using the definition of a logarithm. log_b x= y ⇔ x= b^y The above means that the logarithm y is the exponent to which b must be raised to get x. For our exercise, x is the exponent to which 16 must be raised to get 8. log_(16) 8= x ⇔ 8= 16^x Finally, to solve the exponential equation, we will rewrite the terms so that they have a common base.
8 = 16^x
2^3 = (2^4)^x
2^3 = 2^(4x)
Now we have two equivalent expressions with the same base. If both sides of the equation are equal, the exponents must also be equal.
2^3 = 2^(4x)
3 = 4x
3/4 = x
x = 3/4