Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
4. Rational Expressions
Continue to next subchapter

Exercise 52 Page 533

Factor each denominator and numerator as much as you can and cancel out common factors. The denominator cannot be zero.

C

Practice makes perfect
We want to multiply the given rational expressions. x/x^2-2x-3 * 2x-6/x^2-4x+3 We will start by factoring the numerators and denominators, if possible. Let's start with the first expression.
x/x^2-2x-3
â–¼
Factor the denominator
x/x^2+x-3x-3
x/x(x+1)-3x-3
x/x(x+1)-3(x+1)
x/(x+1)(x-3)
Now, let's factor the second expression.
2x-6/x^2-4x+3
â–¼
Factor the numerator
2(x-3)/x^2-4x+3
â–¼
Factor the denominator
2(x-3)/x^2-x-3x+3
2(x-3)/x(x-1)-3x+3
2(x-3)/x(x-1)-3(x-1)
2(x-3)/(x-1)(x-3)
Now that both expressions have been factored, we will cancel out any common factors.
x/(x+1)(x-3) * 2(x-3)/(x-1)(x-3)
x/(x+1)(x-3) * 2(x-3)/(x-1)(x-3)
x* 2/(x+1)(x-1)(x-3)
2x/(x-1)(x+1)(x-3)
The obtained expression corresponds to the Option C.