Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
4. Properties of Logarithms
Continue to next subchapter

Exercise 6 Page 465

Practice makes perfect
a We want to rewrite the expression log_4 5 + log_4 5 as a single logarithm. For this we can use the Product Property of Logarithms, since this property allows us to rewrite the sum of two same-base logarithmic expressions as the logarithm of the product of their arguments.
log_4 5 + log_4 5

log_4(m) + log_4(n)=log_4(mn)

log_4 (5*5)
log_4 25
Alternatively, we can start by adding their coefficients since they are like terms. Then we can use the Power Property of Logarithms. Recall that this property allows us to rewrite the product of a constant and a logarithmic expression as the logarithm of the argument raised to said constant.
log_4 5 + log_4 5
2log_4 5

m* log_4(a)=log_4(a^m)

log_4 5^2
log_4 25
As we can see, both ways are equally fast and get the same result.
b Now we will rewrite the expression log_5 4 - log_5 6 as a single logarithm. For this we can use the Quotient Property of Logarithms, since this property allows us to rewrite the difference of two same base logarithmic expressions as the logarithm of the quotient of their arguments.
log_5 4 - log_5 6

log_A(m) - log_A(n)=log_A(m/n)

log_5 4/6
log_5 4/6
log_5 2/3