We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 a
We first need to identify the values of a, b, and c.
x^2-9x+15=0 ⇕ 1x^2+( - 9)x+( 15)=0
We see that a= 1, b= - 9, and c= 15. Let's substitute these values into the Quadratic Formula.
Using the Quadratic Formula, we found that the solutions of the given equation are x= 9± sqrt(21)2. Therefore, the solutions are x_1= 9+sqrt(21)2 and x_2= 9-sqrt(21)2.