Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
7. The Quadratic Formula
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Exercise 8 Page 244

Look at the discriminant of the equation.

For one real solution: k=6 or k=-6
For two real solutions: k>6 or k<-6

Practice makes perfect
Recall that we can tell the number of real solutions a quadratic equation has by calculating its discriminant. For a quadratic equation of the form a^2+bx+c=0, the discriminant is given by the expression shown below. b^2-4ac We can find the different possibilities corresponding to different discriminant values in the following table.
Discriminant Number of real solutions
b^2-4ac >0 The function intersects the x-axis two times. There are two real solutions.
b^2-4ac = 0 The function intersects the x-axis one time. There is one real solution.
b^2-4ac < 0 The function does not intersect the x-axis. There are no real solutions.
Comparing the expression 1*x^2+kx+9 with ax^2+bx+c, we can identify that for this case a=1, b=k and c=9. For the equation to have just one real solution the discriminant must vanish. Thus, we have the condition b^2-4ac =0. Let's see its implications for the possible values for k.
b^2-4ac =0
k^2-4(1)(9)=0
k^2 -36 = 0
k^2 = 36
k = ± 6
Therefore, if k=6 or k=-6 the equation will have just one solution.
Now, for the equation to have two real solutions the condition is b^2-4ac >0.
b^2-4ac >0
k^2-4(1)(9)>0
k^2 -36 > 0
k^2 > 36
Notice that since k is squared the inequality is satisfied as long as k>6 or k<-6. Hence, for this values of k the equation would have two real solutions.