Let's start by first identifying the . Then, we will rewrite the expression as a with a of 1.
Factor Out the GCF
The GCF of an expression is a common factor of the terms in the expression. It is the common factor with the greatest and the greatest . In this case, the GCF is
4.
4n2−20n+24
4⋅n2−4⋅5n+4⋅6
4(n2−5n+6)
The result of factoring out a GCF from the given expression is a trinomial with a leading coefficient of
1.
4(n2−5n+6)
Let's temporarily only focus on this trinomial, and we will bring back the GCF after factoring.
Factor the Expression
To factor a trinomial with a leading coefficient of
1, think of the process as multiplying two in reverse. Let's start by taking a look at the constant term.
n2−5n+6
In this case, we have
6. This is a
positive number, so for the product of the constant terms in the factors to be
positive, these constants must have the same (both positive or both negative).
Constants
|
Product of Constants
|
1 and 6
|
6
|
-1 and -6
|
6
|
2 and 3
|
6
|
-2 and -3
|
6
|
Next, let's consider the coefficient of the linear term.
n2−5n+6
For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term,
-5.
Constants
|
Sum of Constants
|
1 and 6
|
7
|
-1 and -6
|
-7
|
2 and 3
|
5
|
-2 and -3
|
-5
|
We found the factors whose product is
6 and whose sum is
-5.
n2−5n+6⇔(n−2)(n−3)
Wait! Before we finish, remember that we factored out a GCF from the original expression. To fully complete the factored expression, let's reintroduce that GCF now.
4(n−2)(n−3)
We can check our answer by applying the and comparing the result with the given expression.
4(n−2)(n−3)
(4n−8)(n−3)
4n(n−3)−8(n−3)
4n2−12n−8(n−3)
4n2−12n−8n+24
4n2−20n+24
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!