Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
Concept Byte: Writing Equations From Roots
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Exercise 1 Page 232

Practice makes perfect
a Recall that a zero of a function is a value of x such that f(x)= 0. In other words, it is the value of x for which the function intercepts the x-axis. Notice that there are infinitely many possible linear functions that satisfy this condition.
Since the only requirement for the function is that its graph must pass through the point ( 3, 0), the slope of the line can take any value we want. We can choose an arbitrary value for the slope and, since we know a point on the line, we can use the point-slope form to write the equation. y- y _1 = m(x- x_1) In this equation m is the slope of the line and ( x_1, y _1) is a known point. We can choose m= 2 and substitute it together with our point of intersection into the point-slope form.
y- y _1 = m(x-x_1)
y- 0 = 2(x- 3)
y = 2(x-3)
y = 2x-6
In order to use function notation, we can replace y with f(x). As a result, we obtain the linear function f(x) = 2x-6. This function has a zero at x=3, as required.
b Now, to find a linear function with a zero at x=4, we will proceed just as we did in Part A. Let's choose a value for the slope, for example m= 3. We know that the line must pass through the point ( 4, 0). Therefore, let's substitute these values into the point-slope form.
y- y _1 = m(x-x_1)
y- 0 = 3(x- 4)
y = 3(x-4)
y = 3x-12
Again, to use function notation we can replace y with g(x). As a result, we obtain the linear function g(x) = 3(x-4).

Recall that this is just an example solution as there are infinitely many lines passing through the required point.