Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Concept Byte: Powers of Complex Numbers
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Exercise 1 Page 265

How can you relate the distances with the exponent of each number?

It will lie on the imaginary-axis at point (0,32).

Practice makes perfect

In Example 1, (2i)^n was computed for n=0, 1, 2, and 3.

n (2i)^n
0 1
1 2i
2 -4
3 -8i

Additionally, these points where plotted on the complex plane.

Our mission is to predict the location of (2i)^5. To do this, we will make a table of values where we point out some important facts from the graph above.

n (2i)^n Location Distance to the Origin
0 1 Real-axis 1
1 2i Imaginary-axis 2
2 -4 Real-axis 4
3 -8i Imaginary-axis 8

The table above leads us to say that (2i)^4 will be on the real-axis, so (2i)^5 will lie on the imaginary-axis. Next, let's rewrite the numbers in the last column.

n (2i)^n Location Distance to the Origin
0 1 Real-axis 2^0
1 2i Imaginary-axis 2^1
2 -4 Real-axis 2^2
3 -8i Imaginary-axis 2^3
4 (2i)^4 Real-axis ?
5 (2i)^5 Imaginary-axis ?

With this last table we can say that the distance from (2i)^4 to the origin is 2^4=16. Since it lies on the real-axis, its coordinates are (16,0). Consequently, the distance from (2i)^5 to the origin is 2^5=32, and because it lies on the imaginary-axis its coordinates are (0,32).

n (2i)^n Location Distance to the Origin
0 1 Real-axis 2^0
1 2i Imaginary-axis 2^1
2 -4 Real-axis 2^2
3 -8i Imaginary-axis 2^3
4 16 Real-axis 16
5 32i Imaginary-axis 32