Concept Byte: Linear Programming
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Each of the equations represents a plane. Before we begin, remember that two lines are enough to define a plane. Therefore, we will need two lines for each plane in order to graph them. -2x-3y+5z=7 & (I) 2x-3y-4z=-4 & (II) Let's graph each plane separately.
x= 0
Zero Property of Multiplication
Identity Property of Addition
| y-intercept | z-intercept | |
|---|---|---|
| Substitute | -3y+5( 0)=7 | -3( 0)+5z=7 |
| Calculate | y= - 7/3 | z= 7/5 |
| Point | ( 0, - 7/3, 0) | ( 0, 0, 7/5) |
y= 0
Zero Property of Multiplication
Identity Property of Addition
| x-intercept | z-intercept | |
|---|---|---|
| Substitute | -2x+5( 0)=7 | -2( 0)+5z=7 |
| Calculate | x= - 3.5 | z= 1.4 |
| Point | ( - 3.5, 0, 0) | ( 0, 0, 1.4) |
We will graph Plane (II) in the same way as we graphed Plane (I). Let's first find two lines such that one line passes through x= 0 and the other through y= 0.
| Substitution | Resulting Equation | |
|---|---|---|
| x=0 | 2( 0)-3y-4z=-4 | -3y-4z=-4 |
| y=0 | 2x-3( 0)-4z=-4 | 2x-4z=-4 |
Next, we will find the intercepts of each line.
| -3y-4z=-4 | 2x-4z=-4 | |||
|---|---|---|---|---|
| Intercept | y-intercept | z-intercept | x-intercept | z-intercept |
| Substitution | -3y-4( 0)=-4 | -3( 0)-4z=-4 | 2x-4( 0)=-4 | 2( 0)-4z=-4 |
| Calculation | y= 4/3 | z= 1 | x= - 2 | z= 1 |
| Point | ( 0, 4/3, 0) | ( 0, 0, 1) | ( - 2, 0, 0) | ( 0, 0, 1) |