Concept Byte: Linear Programming
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Each of the equations represents a plane. Before we begin, remember that two lines are enough to define a plane. Therefore, we will need two lines for each plane in order to graph them. - x+3y+z=6 & (I) -3x+5y-2z=60 & (II) Let's graph each plane separately.
x= 0
Zero Property of Multiplication
Identity Property of Addition
| y-intercept | z-intercept | |
|---|---|---|
| Substitute | 3y+ 0=6 | 3( 0)+z=6 |
| Calculate | y= 2 | z= 6 |
| Point | ( 0, 2, 0) | ( 0, 0, 6) |
y= 0
Zero Property of Multiplication
Identity Property of Addition
| x-intercept | z-intercept | |
|---|---|---|
| Substitute | - x+ 0=6 | - 0+z=6 |
| Calculate | x= - 6 | z= 6 |
| Point | ( - 6, 0, 0) | ( 0, 0, 6) |
We will graph Plane (II) in the same way as we graphed Plane (I). Let's first find two lines such that one line passes through x= 0 and the other through y= 0.
| Substitution | Resulting Equation | |
|---|---|---|
| x=0 | -3( 0)+5y-2z=60 | 5y-2z=60 |
| y=0 | -3x+5( 0)-2z=60 | -3x-2z=60 |
Next, we will find the intercepts of each line to graph them.
| 5y-2z=60 | -3x-2z=60 | |||
|---|---|---|---|---|
| Intercept | y-intercept | z-intercept | x-intercept | z-intercept |
| Substitution | 5y-2( 0)=60 | 5( 0)-2z=60 | -3x-2( 0)=60 | -3( 0)-2z=60 |
| Calculation | y= 12 | z= -30 | x= -20 | z= -30 |
| Point | ( 0, 12, 0) | ( 0, 0, -30) | ( -20, 0, 0) | ( 0, 0, -30) |