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The line of best fit is a line that approximates the relationship between the variables or data sets of a scatter plot. Begin by sketching it!
Use the equation of the line of best fit.
Use the equation of the line of best fit.
Line of Best Fit:
13.3 grams of fat
See solution
Let x and y be the grams of fat and the number of calories, respectively.
| Fast Food Calories | |||||||||
|---|---|---|---|---|---|---|---|---|---|
| Restaurant | A | B | C | D | E | F | G | H | I |
| Number of Calories | 720 | 530 | 510 | 500 | 305 | 410 | 440 | 320 | 598 |
| Grams of fat | 46 | 30 | 27 | 26 | 13 | 20 | 25 | 13 | 26 |
Let's plot the points on the coordinate plane.
The line of best fit is a line that approximates the relationship between the variables or data sets of a scatter plot. Let's sketch it!
To write the equation of the line, we should first determine its slope. Therefore, we will choose two points on the line. Looking at the graph, we can choose the points (20,410) and (30,530). Let's use the Slope Formula!
Substitute ( 20,410) & ( 30,530)
Subtract terms
Calculate quotient
Now that we know the slope of the line and a point that it passes through, we can write the equation in the point-slope form. Let (20,410) be our reference point. y-y_1=m(x-x_1) ⇕ [0.5em] y-410=12(x-20) By isolating y, we can rewrite the equation in slope-intercept form to make it a bit easier to understand.
By substituting 330 for y into the equation that we wrote in Part A, we will estimate the amount of fat.
y= 330
LHS-170=RHS-170
.LHS /12.=.RHS /12.
Round to 1 decimal place(s)
Rearrange equation
Therefore, the amount of fat in a 330-Calorie hamburger would be 13.3 grams.
Let's use the equation of the line of best fit to determine which estimation is not reasonable. We will first substitute 200 for y and find x.
y= 200
LHS-170=RHS-170
.LHS /12.=.RHS /12.
Rearrange equation
By the equation, we found that a 200-Calorie hamburger contains 2.5 grams of fat, which is not close to the given amount of fat 10 grams. This means that it is not reasonable. Next, we will find the amount of fat that a 660-Calorie hamburger contains in the same way.
| Hamburger | y=12x+170 | Estimated Fat | Given Fat |
|---|---|---|---|
| 200-Calorie | 200=12x+170 | 2.5 grams | 10 grams |
| 660-Calorie | 660=12x+170 | 40.8 grams | 36 grams |
A 660-Calorie hamburger contains 40.8 grams of fat, which is close to the given amount of fat 36. Therefore, it is reasonable.