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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

4. More About Linear Equations

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Exercise 1 Page 86

Substitute the given point and slope into the slope-intercept form of an equation.

y=-3 x - 1

Practice makes perfect

Equations in slope-intercept form follow a certain format. y=mx+ b In this form, m is the slope and b is the y-intercept. The line has a slope of -3 which means that we can substitute m=-3. y=-3x+ b To write a complete equation for this line, we also need to determine the y-intercept b. We can do that by substituting the given point (1,-4) into the equation and solving for b.

y=-3x+b

x= 1, y= - 4

- 4=-3( 1)+b

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Solve for b

Multiply

-4 = -3 +b

LHS+3=RHS+3

- 1=b

Rearrange equation

b= - 1

Now that we have both the slope and the y-intercept, we can write the final equation. y=-3x+( - 1) ⇔ y=-3x - 1

Subchapter links

Lesson Check p.86

Practice and Problem-Solving Exercises p.86-88

Standardized Test Prep p.88

Mixed Review p.88