Pearson Algebra 1 Common Core, 2015
PA
Pearson Algebra 1 Common Core, 2015 View details
4. Factoring to Solve Quadratic Equations
Continue to next subchapter

Exercise 1 Page 570

Use the Zero Product Property to solve the given equation.

4, 7

Practice makes perfect
To solve this equation, we will apply the Zero Product Property.
(v-4)(v-7)=0
lcv-4=0 & (I) v-7=0 & (II)
lv=4 v-7=0
lv_1=4 v_2=7

Checking Our Answer

Checking our answer
We can substitute our solutions back into the given equation and simplify to check if our answers are correct. We will start with v=4.
(v-4)(v-7)=0
( 4-4)( 4-7)? =0
â–Ľ
Simplify
0(-3)? =0
0=0 âś“
Substituting and simplifying created a true statement, so we know that v=4 is a solution of the equation. Let's move on to v=7.
(v-4)(v-7)=0
( 7-4)( 7-7)? =0
â–Ľ
Simplify
3(0)? =0
0=0 âś“
Again, we created a true statement. v=7 is indeed a solution of the equation.