Exercise 1 Page 291

To determine if a point satisfies an equation, we substitute the point into the equation and simplify. If the resulting statement is true, then the point is the solution. Let's test the given point.

4y+2x=3

SubstituteII

x= 1.5, y= 0

4( 0)+2( 1.5)=3

ZeroPropMult

Zero Property of Multiplication

2(1.5)=3

Multiply

Multiply

3=3

Our resulting statement, 3=3, is true. Therefore the point (1.5,0) is the solution of the equation.