Start by identifying the values of each term's coefficient.
(2c+1)(c+14)
Practice makes perfect
We want to completely factor the given expression. Here we have a quadratic trinomial of the form ac^2+bc+d, where |a| ≠1 and there are no common factors. To factor this expression we will rewrite the middle term, bc, as two terms. The coefficients of these two terms will be factors of ad whose sum must be b.
2c^2+29c+14 ⇔ 2c^2+29c+14
We have that a= 2, b=29, and d=14. There are now three steps we need to follow in order to rewrite the above expression.
Find a d. Since we have that a= 2 and d=14, the value of a d is 2* 14=28.
Find factors of a d. Since a d=28, which is positive, we need factors of a d to have the same sign — both positive or both negative — in order for the product to be positive. Since b=29, which is positive, those factors will need to be positive so that their sum is positive.
We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!
