Sign In
If there is no greatest common factor between the terms, rewrite the linear term as a sum of two terms.
(m-9)(m+2)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
m^2-7m-18
⇕
m^2-7m+(- 18)
In this case, we have -18. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative.)
| Factor Constants | Product of Constants |
|---|---|
| 1 and - 18 | - 18 |
| - 1 and 18 | - 18 |
| 2 and - 9 | - 18 |
| - 2 and 9 | - 18 |
| 3 and - 6 | - 18 |
| - 3 and 6 | - 18 |
Next, let's consider the coefficient of the linear term. m^2-7m+(- 18) For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, - 7.
| Factors | Sum of Factors |
|---|---|
| 1 and - 18 | - 17 |
| -1 and 18 | 17 |
| 2 and - 9 | -7 |
| -2 and 9 | 7 |
| 3 and - 6 | - 3 |
| -3 and 6 | 3 |
We found the factors whose product is - 18 and whose sum is -7. m^2-7m+(- 18) ⇔ (m-9)(m+2)
Distribute (m+2)
Distribute m
Distribute - 9
Subtract term
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!