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Make a table of values and connect the points with a parabola.
Graph:
Axis of Symmetry: x=-3/4
Vertex: (-3/4,89/8)
To draw the graph of the given quadratic function written in standard form, let's start by identifying the values of a, b, and c. y=-2 x^2-3x+10 ⇔ y=-2x^2+(-3)x+10 We can see that a=-2, b=-3, and c=10. Now, we will follow three steps.
The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
The axis of symmetry of the parabola is the vertical line with equation x=- 34.
To calculate the vertex, we need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2a, f( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=- 34. Thus, the x-coordinate of the vertex is also - 34. To find the y-coordinate, we need to substitute - 34 for x in the given equation.
x= -3/4
(a/b)^m=a^m/b^m
Multiply
- a(- b)=a* b
a/b=a * 4/b * 4
a = 16* a/16
Add fractions
a/b=.a /2./.b /2.
We found the y-coordinate, and now we know that the vertex is (- 34, 898). Rewriting the y-coordinate as a decimal, we can tell it is approximately 11.1.
To graph the function we will make a table of values.
| x | - 2x^2-3x+10 | y=- 2x^2-3x+10 |
|---|---|---|
| -3 | - 2( -3)^2-3( -3)+10 | 1 |
| -2 | - 2( -2)^2-3( -2)+10 | 8 |
| 0 | - 2( 0)^2-3( 0)+10 | 10 |
| 1 | - 2( 1)^2-3( 1)+10 | 5 |
| 2 | - 2( 2)^2-3( 2)+10 | -4 |
Now, let's plot the obtained points, then we can connect them with a parabola.