Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 10 Page 604

Make a table of values and connect the points with a parabola.

Graph:

Axis of Symmetry: x=-3/4
Vertex: (-3/4,89/8)

Practice makes perfect

To draw the graph of the given quadratic function written in standard form, let's start by identifying the values of a, b, and c. y=-2 x^2-3x+10 ⇔ y=-2x^2+(-3)x+10 We can see that a=-2, b=-3, and c=10. Now, we will follow three steps.

  1. Find the axis of symmetry.
  2. Calculate the vertex.
  3. Graph the function.

    Finding the Axis of Symmetry

    The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.

    x=- b/2a
    x=-( -3/2(- 2))
    â–¼
    Simplify right-hand side
    x=- (-3/- 4)
    x=-3/4

    The axis of symmetry of the parabola is the vertical line with equation x=- 34.

    Calculating the Vertex

    To calculate the vertex, we need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2a, f( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=- 34. Thus, the x-coordinate of the vertex is also - 34. To find the y-coordinate, we need to substitute - 34 for x in the given equation.

    y=-2 x^2-3x+10
    y=-2 ( -3/4)^2-3( -3/4)+10
    â–¼
    Simplify right-hand side
    y=-2 (9/16)-3(-3/4)+10
    y=-18/16-3(-3/4)+10
    y=-18/16+9/4+10
    y=-18/16+36/16+10
    y=-18/16+36/16+160/16
    y=178/16
    y=89/8

    We found the y-coordinate, and now we know that the vertex is (- 34, 898). Rewriting the y-coordinate as a decimal, we can tell it is approximately 11.1.

    Graphing the function

    To graph the function we will make a table of values.

    x - 2x^2-3x+10 y=- 2x^2-3x+10
    -3 - 2( -3)^2-3( -3)+10 1
    -2 - 2( -2)^2-3( -2)+10 8
    0 - 2( 0)^2-3( 0)+10 10
    1 - 2( 1)^2-3( 1)+10 5
    2 - 2( 2)^2-3( 2)+10 -4

    Now, let's plot the obtained points, then we can connect them with a parabola.