Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Systems of Linear Inequalities
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Exercise 39 Page 405

Substitute the given point into the given systems.

A

Practice makes perfect

The given point is a solution to a system of inequalities if it satisfies every inequality in the system. Let's substitute the point into the given systems one at a time until we find the correct one.

Option A

If the given point satisfies both inequalities at the same time, the point is a solution to the system. Let's substitute the point into both inequalities of the system.

,

Add and subtract terms

Because we obtained true statements from both inequalities by substituting the point it is a solution to the system in option A.

Checking the Remaining Options

Although option A is correct, let’s verify our answer by checking the remaining options as well. To do so, we will following the same procedure for each of the remaining systems.

System Substitution Simplify

When we substitute the point into any of the remaining systems, at least one of the inequalities is not satisfied. Therefore, the point is not a solution of any of the remaining systems. This means that, as we discovered at the beginning of our solution, the correct answer is indeed option A.