Sign In
A
The given point (- 3,11) is a solution to a system of inequalities if it satisfies every inequality in the system. Let's substitute the point into the given systems one at a time until we find the correct one.
If the given point satisfies both inequalities at the same time, the point is a solution to the system. Let's substitute the point into both inequalities of the system.
(I), (II): x= -3, y= 11
(II): a(- b)=- a * b
(I), (II): Add and subtract terms
Because we obtained true statements from both inequalities by substituting the point (-3,11), it is a solution to the system in option A.
Although option A is correct, let’s verify our answer by checking the remaining options as well. To do so, we will following the same procedure for each of the remaining systems.
| System | Substitution | Simplify |
|---|---|---|
| y > x+8 3x+y > 2 | 11 > - 3+8 3( -3)+ 11 > 2 | 11 > 5 ✓ 2 > 2 * |
| y > - x+8 2x+3y ≥ 7 | 11 > - ( -3)+8 2( -3)+3( 11) ≥ 7 | 11 > 11 * 27 ≥ 7 ✓ |
| y≤ -3x+1 x-y≥ -15 | 11≤ -3( -3)+1 -3- 11≥ -15 | 11≤ 10 * - 14≥ -15 ✓ |
When we substitute the point (- 3, 11) into any of the remaining systems, at least one of the inequalities is not satisfied. Therefore, the point (-3,11) is not a solution of any of the remaining systems. This means that, as we discovered at the beginning of our solution, the correct answer is indeed option A.