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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

8. Graphing Absolute Value Functions

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Exercise 41 Page 350

You'll need to substitute 0 and solve for x.

1/2

Practice makes perfect

Think of the point where the graph of an equation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the equation, we should substitute 0 for y and solve for x.

y=-4x+2

y= 0

0=-4x+2

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Solve for x

LHS-2=RHS-2

-2=-4x

.LHS /(-4).=.RHS /(-4).

-2/-4=x

a/b=.a /(-2)./.b /(-2).

1/2=x

Rearrange equation

x=1/2

An x-intercept of 12 means that the graph passes through the x-axis at the point ( 12,0).

Subchapter links

Lesson Check p.348

Practice and Problem-Solving Exercises p.349-350

Standardized Test Prep p.350

Mixed Review p.350