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1.4 feet
We want to paint a wall by painting a blue border with width x around a white rectangle.
We are asked to find the approximate width x that makes the area of the blue border and the area of the white rectangle the same. To do so, we will first find the mentioned areas one by one and then set them equal. Let's begin by finding the area of the white rectangle.
We can find the side lengths of the white rectangle by using the given figure.
Distribute 8-2x
Distribute 12
Distribute - 2x
Subtract term
Commutative Property of Addition
Next, we will find the area of the blue border.
To find the area of the border we will subtract the area of the white rectangle from the area of the entire wall. Area of the Blue Border = Area of the Wall - Area of the White Rectangle We found the area of the white rectangle in the previous subheading. We will find the area of the entire wall as well. Area of the Wall &= 8* 12 &= 96 Now we are ready to write an expression for the area of the blue border.
-(b-a)=a-b
Commutative Property of Addition
Subtract term
As we found the required areas, we can find the approximate value of x.
We want the areas of the blue border and the white rectangle to be equal. Therefore, let's equate them to find x.
Substitute values
LHS+4x^2=RHS+4x^2
LHS-40x=RHS-40x
Factor out 8
.LHS /8.=.RHS /8.
Rearrange equation
To find the approximate value of x we will use the Quadratic Formula.
Substitute values
- (- a)=a
a * 1=a
Calculate power
Multiply
Subtract terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 2
Cancel out common factors
Use a calculator
Since the width of the entire wall is 8 feet, the width of the border needs to be smaller than 8 feet. x_1 ≈ 8.6 x_2 ≈ 1.4 Therefore, x is approximately 1.4 feet.