Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Graphing Square Root Functions
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Exercise 53 Page 643

Practice makes perfect
a

We are asked to determine if the given graph of x=y^2 is a graph of a function.

In order to do that, recall that a function is a relation in which each input value corresponds to exactly one output value. In our case, we need to check that each x-value corresponds to no more than one y-value. We can check this using the Vertical Line Test.

As we can see, all but one x-value, the point at (0,0), corresponds to two y-values. Therefore, the given graph does not illustrate a function.

b

To determine the relation between x=y^2 and the square root function y=sqrt(x), let's solve the first of these equations for y.

x=y^2
â–¼
Solve for y
sqrt(x)=sqrt(y^2)
sqrt(x)=|y|
|y|=sqrt(x)
Using the properties of absolute values, this equation can be split into two equations. lc y ≥ 0:y = sqrt(x) & (I) y < 0:y = - sqrt(x) & (II) As we can see, the Equation (I) is the same equation as the square root function that we were given. Therefore, y=sqrt(x) is the upper half of the relation described by x=y^2.

c

Let's start by identifying which part of the given graph is shown in Quadrant IV.

In Part B, we found that the equation x=y^2 can be written as the following two equations. x=y^2 ⇒ lcy=sqrt(x) & (I) y=- sqrt(x) & (II) The graph of the Equation (I) is the upper half of the graph of x=y^2 and it is shown in Quadrant I. Therefore, the lower part of the graph — shown in Quadrant IV — is the graph of the Equation (II).

To double check this conclusion, we can graph y=- sqrt(x) by making a table of values.

x 0 1 2 4 9
Substitute y=- sqrt(0) y=- sqrt(1) y=- sqrt(2) y=- sqrt(4) y=- sqrt(9)
y 0 - 1 - 1.4 - 2 - 3

Now, we can plot the points and connect them with a smooth curve.

Another possible way to graph this function is by reflecting the graph of y=sqrt(x) over the x-axis. Either way, we get the exact same graph as the part of x=y^2 that is shown in Quadrant IV.