Sign In
Solve x=y^2 for y or compare the graph of y=sqrt(x) to the graph of x=y^2.
Use the information from Part B. Note that the lower part of the graph is a reflection of the upper part of the graph.
No, see solution.
See solution.
y=- sqrt(x), see solution.
We are asked to determine if the given graph of x=y^2 is a graph of a function.
In order to do that, recall that a function is a relation in which each input value corresponds to exactly one output value. In our case, we need to check that each x-value corresponds to no more than one y-value. We can check this using the Vertical Line Test.
As we can see, all but one x-value, the point at (0,0), corresponds to two y-values. Therefore, the given graph does not illustrate a function.
To determine the relation between x=y^2 and the square root function y=sqrt(x), let's solve the first of these equations for y.
sqrt(LHS)=sqrt(RHS)
sqrt(a^2)=|a|
Rearrange equation
Let's start by identifying which part of the given graph is shown in Quadrant IV.
In Part B, we found that the equation x=y^2 can be written as the following two equations.
To double check this conclusion, we can graph y=- sqrt(x) by making a table of values.
| x | 0 | 1 | 2 | 4 | 9 |
|---|---|---|---|---|---|
| Substitute | y=- sqrt(0) | y=- sqrt(1) | y=- sqrt(2) | y=- sqrt(4) | y=- sqrt(9) |
| y | 0 | - 1 | - 1.4 | - 2 | - 3 |
Now, we can plot the points and connect them with a smooth curve.
Another possible way to graph this function is by reflecting the graph of y=sqrt(x) over the x-axis. Either way, we get the exact same graph as the part of x=y^2 that is shown in Quadrant IV.