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Recall the definition of a midpoint of a segment.
See solution.
\begin{gathered} \underline\textbf{Statement}\\ \text{If } Y \text{ is the midpoint of } \overline{XZ} \text{ and } \\ Z \text{ is the midpoint of } \overline{YW}, \\ \text{then from the definition of a midpoint} \\ \text{of a segment } XY=YZ \text{ and } YZ=ZW. \end{gathered} Now, notice that we can substitute ZW for YZ in the equation XY=YZ. Then, we will get XY= ZW. \begin{gathered} \underline\textbf{Statement}\\ \text{By substitution, } XY=ZW. \end{gathered} Finally, by the definition of congruence, if two segments have the same measure, then they are congruent. Therefore, XY ≅ ZW, which is what we wanted to prove. \begin{gathered} \underline\textbf{Statement}\\ \text{By the definition of congruence, if two segments} \\ \text{have the same measure, then they are} \\ \text{congruent. Thus, } \overline{XY} \cong \overline{ZW}. \end{gathered}
Given:& Y is the midpoint of XZ and & Z is the midpoint of YW
Prove:& XY ≅ ZW
Prove:
If Y is the midpoint of XZ and Z is the midpoint of YW, then from the definition of a midpoint of a segment XY=YZ and YZ=ZW. By substitution, XY=ZW. By the definition of congruence, if two segments have the same measure, then they are congruent. Thus, XY ≅ ZW.