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Raise both sides of the equation to the second power.
40
We will find and check the solution of the given equation.
To solve an equation with a variable expression inside a radical, we first want to make sure the radical is isolated. Then we can raise both sides of the equation to the second power. Let's try to solve our equation using this method!
LHS^2=RHS^2
( sqrt(a) )^2 = a
Calculate power
.LHS /10.=.RHS /10.
The solution of our equation is x= 40. Now, let's check whether our solution is extraneous.
To check our solution, we will substitute 40 for x into the original equation. If we obtain a true statement, the solution is not extraneous. Otherwise, the solution is extraneous.
x= 40
Multiply
Calculate root
We got a true statement, so x=40 is the solution of the original equation.