McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Practice Test
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Exercise 28 Page 267

Raise both sides of the equation to the second power.

40

We will find and check the solution of the given equation.

Finding the Solution

To solve an equation with a variable expression inside a radical, we first want to make sure the radical is isolated. Then we can raise both sides of the equation to the second power. Let's try to solve our equation using this method!
sqrt(10x)=20
(sqrt(10x))^2=20^2
10x=20^2
10x=400
x=40
The solution of our equation is x= 40. Now, let's check whether our solution is extraneous.

Checking the Solution

To check our solution, we will substitute 40 for x into the original equation. If we obtain a true statement, the solution is not extraneous. Otherwise, the solution is extraneous.
sqrt(10x)=20
sqrt(10( 40))? =20
sqrt(400)? =20
20=20 âś“
We got a true statement, so x=40 is the solution of the original equation.