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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Standardized Test Practice

Exercise 1 Page 89

Apply the Zero Product Property after factoring.

F

Practice makes perfect

To solve the given equation, we first need to factor it.

x^2+6x-112=0

Write as a difference

x^2+14x-8x-112=0

▼

Factor out x & (- 8)

Factor out x

x(x+14)-8x-112=0

Factor out - 8

x(x+14)-8(x+14)=0

Factor out (x+14)

(x-8)(x+14)=0

Now, we will apply the Zero Product Property.

(x-8)(x+14)=0

Use the Zero Product Property

lcx-8=0 & (I) x+14=0 & (II)

(I): LHS+8=RHS+8

lx=8 x+14=0

(II): LHS-14=RHS-14

lx_1=8 x_2=- 14

The solutions to the equation are 8 and - 14. Therefore, the answer is F.

Subchapter links

Multiple Choice p.89

Short Response/Gridded Response p.89

Extended Response p.89