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Let's analyze the given quadrilateral to find the variables x and y. Keep in mind, we have been told that the figure is a rectangle.
By the Segment Addition Postulate, we can express each diagonal as the sum of its smaller segments.
FH= FM+MH and GJ=GM+MJ
| Equation | FH=FM+MH | GJ=GM+MJ |
|---|---|---|
| Substitution | FH=FM+ FM | GJ=GM+ GM |
| Simplification | FH=2FM | GJ=2GM |
| Substitution | FH=2( 3x+y) | GJ=2( 13) |
Recall that the diagonals of a rectangle are congruent. Therefore, their lengths are equal. FH=GJ ⇔ 2(3x+y)=2(13) Because our quadrilateral is a rectangle, both opposite sides are congruent. We can use the given expressions to write one more equation. GH=FJ ⇔ 11=- 3x + 5y Let's create a system of equations using both equations above. 2(3x+y)=2(13) 11=-3x+5y To solve it we will use the Substitution Method.
(I): .LHS /2.=.RHS /2.
(I): LHS-3x=RHS-3x
(II): y= 13-3x
(II): Distribute 5
(II): Add and subtract terms
(II): LHS+18x=RHS+18x
(II): LHS-11=RHS-11
(II): .LHS /18.=.RHS /18.
Now that we have found x, we can substitute it in the first equation to find y.
(I): x= 3
(I): Multiply
(I): Subtract term
Therefore, the correct answer is A.