For a right triangle with legs a and b and hypotenuse c, the following is true: a^2+b^2=c^2.
Using this theorem, we can write the following relation.
XY^2 + ZY^2 = XZ^2
Let's substitute the given expressions for XW, WZ, and XZ into the equation.
8^2 + 6^2 = (2c)^2
Let's solve for c.
Since the length of a segment cannot be negative, we know that c=5.
XZ=2( 5) ⇔ XZ=10
Recall that the diagonals of a rectangle are congruent. Therefore, their lengths are equal.
WY=XZ ⇔ WY=10
