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McGraw Hill Glencoe Geometry, 2012

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McGraw Hill Glencoe Geometry, 2012 View details

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Exercise 1 Page 777

To find the length of the rectangle, we will use the given information and the formula for the area of a rectangle.

A = ℓ \cdot w

We will substitute the given measures,

A = 25

and

w = 5,

into the above formula to calculate

ℓ .

A = ℓ \cdot w

$A = 25$ , $w = 5$

25 = ℓ \cdot 5

▼

Solve for

ℓ

$LHS / 5 = RHS / 5$

5 = ℓ

Rearrange equation

ℓ = 5

The length of the rectangle is

5 units .

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