McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
7. Three-Dimensional Figures
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Exercise 22 Page 71

Surface Area: 800 ft^2
Volume: 1280 ft^3

Practice makes perfect

Let's first calculate the surface area and then the volume.

Surface Area

The given solid is a pyramid.

To calculate the surface area of a pyramid, we can use the known formula where P is the perimeter of the base, l is the slant height, and B is the area of the base. S=1/2Pl+B The base of the pyramid is a square with the side length of 16 feet. Let's calculate its perimeter! P=4s ⇒ P&=4( 16) &=64ft The area of the square equals the squared length of the side. B=s^2 ⇒ B&= 16^2 &=256ft^2 We are also given that the slant height l is 17 feet. Let's substitute all of these values into the formula for the surface area and calculate it.
S=1/2Pl+B
S=1/2(64)( 17)+256
Simplify right-hand side
S=1/2(1088)+256
S=1088/2+256
S=544+256
S=800
The surface area of the pyramid is 800 square feet.

Volume

The volume of a pyramid can also be calculated using a known formula. V=1/3Bh Once again, B is the area of the base, and h is the height. We already found that the area of the pyramid's base is 256 square feet. We are also given that the height is 15 feet. Let's substitute these values into the formula and calculate V.
V=1/3Bh
V=1/3( 256)( 15)
Simplify right-hand side
V=1/3(3840)
V=3840/3
V=1280
The volume of the pyramid is 1280 cubic feet.