McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
7. Three-Dimensional Figures
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Exercise 5 Page 70

Practice makes perfect
a Using the given information, we can draw a model of the cone-shaped hats created for the party.

Now we can use the formula for the volume of a cone to calculate the volume of the hats. V=1/3Ï€ r^2 h In this formula, r is the radius and h is the height of the cone. We know that the cone is 6.5 inches tall. We are also given a diameter of the cone's base. Since we need to know the radius, let's divide the diameter of 4 inches by 2. r=4/2=2inches Now, we can substitute the values of the radius and height into the formula, and calculate the volume.

V=1/3Ï€ r^2 h
V=1/3Ï€ (2)^2( 6.5)
V=1/3Ï€( 4)( 6.5)
V=27.21333...
V≈ 27.2

The volume of candy that will fill the cone is approximately 27.2 in^3.

b Lawana makes the cone-shaped hats by hand, so to find the area of the material she needs, we should calculate the surface area of a cone. We can use a modified version of the formula for surface area. We do not need to include the area of the base because this is where a head will go!
SA_(cone) (including the Base)=& π rl+ π r^2 SA_(cone)(excluding the Base)=& π rl In this formula, r is the radius and l is the slant height of the cone. We know both of them, so let's substitute these values into the formula.

SA=Ï€ rl
SA=Ï€( 2)( 6.8)
SA= 13.6Ï€
SA= 42.704...
SA≈ 42.7

Around 42.7 in^2 of the material is needed.