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McGraw Hill Glencoe Geometry, 2012

MH

McGraw Hill Glencoe Geometry, 2012 View details

2. Linear Measure

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Exercise 8 Page 18

Draw a figure to represent the given information.

$x = 3$ and $B C = 3$

Practice makes perfect

We need to find the value of $x$ and $B C .$ Let's start by drawing a figure to represent the given information. We know that $B$ is between $C$ and $D .$

Now that we have our points drawn on a segment, we can label the lengths with the given values.

We are also given that

C D = 17,

so we can use the Segment Addition Postulate to help us create an equation that can be solved for

x .

C D = C B + B D \Leftrightarrow 17 = 4 x - 9 + 3 x + 5

We can now use the Properties of Equality to solve for

x .

17 = 4 x - 9 + 3 x + 5

Add terms

17 = 7 x - 4

$LHS + 4 = RHS + 4$

21 = 7 x

$LHS / 7 = RHS / 7$

3 = x

Rearrange equation

x = 3

Now that we have the value for

x,

let's substitute it into the expression

4 x - 9

to find the length of

B C .

B C = 4 x - 9

$x = 3$

B C = 4 (3) - 9

Multiply

B C = 12 - 9

Subtract term

B C = 3

We found that

x = 3

and

B C = 3 .

Subchapter links

Check Your Understanding p.18

Practice and Problem Solving p.18-20

H.O.T. Problems p.20

Standardized Test Practice p.21

Spiral Review p.21

Skills Review p.21