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What is the formula for the area of a parallelogram? Use it to find the length of the longer side of each parallelogram.
4x^2+9x-5/2 square meters
Let's consider the given diagram.
We are also given the height and area of parallelogram F and G.
| Parallelogram | Height | Area |
|---|---|---|
| F | h_F=2x+3 | A_F=8x^2+10x-3 |
| G | h_G=3x-1 | A_G=6x^2+13x-5 |
To find the area of the right triangle H, we need to find the lengths b_F and b_G.
Substitute the expressions for the height and area of the parallelogram F into the formula.
h_F= 2x+3, A_F= 8x^2+10x-3
Rewrite 8x^2+10x-3 as (4x-1)(2x+3)
Cancel out common factors
Simplify quotient
We have that b_F=4x-1.
Again, let's substitute the expressions for the height and the area of the parallelogram G into the formula.
h_G= 3x-1, A_G= 6x^2+13x-5
Rewrite 6x^2+13x-5 as (2x+5)(3x-1)
Cancel out common factors
Simplify quotient
We have that b_G=2x+5.
Knowing the lengths b_F and b_G, we can calculate the area of the triangle H. It is a right triangle, so to find its area we have to multiply the lengths of its legs and divide by 2.
Therefore, the formula for the triangle H can be written as follows. A_H=1/2b_Fb_G Finally, let's substitute the values of b_F and b_G and simplify.
The area of the triangle H is 4x^2+9x- 52 square meters.