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What differences do you see between the given function and the parent function? Apply those transformations to the graph of the parent function, f(x)=sqrt(x).
Graph:
Domain: D = { x | x ≥ 0 }
Range: R = { f(x) | f(x) ≥ - 2 }
The given function is a square root function.
f(x)=sqrt(x)- 2
The graph of it will be a transformed version of the parent function, y=sqrt(x). Square root functions typically follow the same general format.
f(x)= asqrt(x- h)+ k
To graph the given function, let's show the possible transformations of f(x)=sqrt(x).
| Transformations of f(x) | |
|---|---|
| Vertical Translations | Translation up k units, k>0 y=f(x)+ k |
| Translation down k units, k>0 y=f(x)- k | |
| Horizontal Translations | Translation right h units, h>0 y=f(x- h) |
| Translation left h units, h>0 y=f(x+ h) | |
| Vertical Stretch or Shrink | Vertical stretch, a>1 y= af(x) |
| Vertical shrink, 0< a<1 y= af(x) | |
| Reflections | In the x-axis y= - f(x) |
| In the y-axis y= f(- x) | |
Using the table, we can graph the function as a series of transformations. Let's begin with the parent function.
Now, we will translate the graph 2 units down by subtracting 2 to each of the y-coordinates.
Finally, we have the graph of the given function.
To determine the domain of the function, recall that the radicand cannot be negative. x ≥ 0 Therefore, the possible values of x are those such that x≥ 0. By substituting the minimum value of the domain into the function, we can find the minimum value of the range.
This tells us that the range is all values of f(x) such that f(x) ≥ - 2. Domain:& { x | x ≥ 0 } Range:& { f(x) | f(x) ≥ - 2 }