McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
5. Operations with Radical Expressions
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Exercise 73 Page 421

Start by drawing the boundary curve. Recall that the domain of radical functions only includes values for which the radicand is non-negative.

Practice makes perfect

To graph the given inequality, we will start by drawing its boundary curve. y=sqrt(x-2) To do so, we first need to find the domain. For radical functions, the domain only includes values for which the radicand is non-negative.

x-2 ≥ 0
x ≥ 2

Now we will make a table of values, using a variety of values for x greater than or equal to 2.

x sqrt(x-2) y=sqrt(x-2)
2 sqrt(2-2) 0
3 sqrt(3-2) 1
4 sqrt(4-2) ≈ 1.41
5 sqrt(5-2) ≈ 1.73
6 sqrt(6-2) 2
7 sqrt(7-2) ≈ 2.24
8 sqrt(8-2) ≈ 2.45

Let's plot the points and connect them with a smooth curve.

Finally, we can determine the region to shade using a test point. If the test point produces a true statement when substituted into the given inequality, we will shade the region that contains it. If it produces a false statement, we will shade the region which does not contain the test point. We will use the point (3,0).

y≤sqrt(x-2)
0? ≤sqrt(3-2)
0? ≤sqrt(1)
0≤ 1 ✓

Since the point produced a true statement, we will shade the region that contains (3,0). Note that we are not given a strict inequality, so the curve will be solid.