McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
3. Solving Quadratic Equations by Factoring
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Exercise 6 Page 242

Try to rewrite the middle term, bx, as two terms.

(x-4)(x-8)

Practice makes perfect
To factor a trinomial with a leading coefficient of one, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2-12x+32 In this case, we have 32. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)
Factor Constants Product of Constants
1 and 32 32
-1 and -32 32
2 and 16 32
-2 and -16 32
4 and 8 32
-4 and -8 32

Next, let's consider the coefficient of the linear term. x^2-12x+32 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, -12.

Factors Sum of Factors
1 and 32 33
-1 and -32 -33
2 and 16 18
-2 and -16 - 18
4 and 8 12
- 4 and - 8 -12

We found the factors whose product is 32 and whose sum is -12. x^2-12x+32 ⇔ (x-4)(x-8)