Sign In
Follow each step of the instructions.
Express the length of the segments in terms of x.
Use exact values in the table.
Think of the relationship between x and CQ.
Construction:
x=1+sqrt(5)/2
Table:
| CQ | x |
|---|---|
| 1 | 1+sqrt(5)/2 |
| 2 | 1+sqrt(5) |
| 3 | 3+3sqrt(5)/2 |
| 4 | 2+2sqrt(5) |
Example Solution: x=n*1+sqrt(5)/2
Let's follow each step of the instructions. We start with a square and the midpoint of CD.
Finally, we extend AB and draw a perpendicular from Q to DQ to construct the rectangle ARQD.
We are given that AD=x, and we know that ABCD is a square and ARQD is a rectangle. This means that we have several congruent segments on the figure all with measure x. Let's mark these on the figure.
We are also given that CQ=1.
Let's express the length of the segments involved in the given equation in terms of x.
DQ&=x+1
AD&=x
QR&=x
CQ&=1
Substitute expressions
a/1=a
LHS * x=RHS* x
LHS-x=RHS-x
Rearrange equation
We are asked to use the method of completing the square to solve this equation. This method involves creating a complete square on the left hand side of the equation by adding the square of half the coefficient of the linear term to each side. x^2+ bx=d ⇕ x^2+ bx+(b/2)^2=d+(b/2)^2 ⇕ (x+b/2)^2=d+(b/2)^2 In our case b= -1, so we add ( -12)^2= 14 to each side.
LHS+1/4=RHS+1/4
a^2-2ab+b^2=(a-b)^2
Add terms
We can now use the Square Root Property to finish solving the equation.
sqrt(LHS)=sqrt(RHS)
LHS+1/2=RHS+1/2
Since x represents a length, it is certainly not negative. x=1+sqrt(5)/2
We can use the method in Part B to find x for different values of CQ.
| CQ | Equation | Rearranged Equation | Completed Square | Positive Solution |
|---|---|---|---|---|
| 1 | x+1/x=x/1 | x^2-x=1 | (x-1/2)^2=5/4 | x=1+sqrt(5)/2 |
| 2 | x+2/x=x/2 | x^2-2x=4 | (x-1)^2=5 | x=1+sqrt(5) |
| 3 | x+3/x=x/3 | x^2-3x=9 | (x-3/2)^2=45/4 | x=3+3sqrt(5)/2 |
| 4 | x+4/x=x/4 | x^2-4x=16 | (x-2)^2=20 | x=2+2sqrt(5) |
To find a pattern, let's rewrite all values of x as a fraction with the common denominator 2.
| CQ | x | Fraction Form |
|---|---|---|
| 1 | 1+sqrt(5)/2 | 1+sqrt(5)/2 |
| 2 | 1+sqrt(5) | 2+2sqrt(5)/2 |
| 3 | 3+3sqrt(5)/2 | 3+3sqrt(5)/2 |
| 4 | 2+2sqrt(5) | 4+4sqrt(5)/2 |
From this table, we can form a conjecture. IfCQ=n,thenx=n+nsqrt(5)/2=n*1+sqrt(5)/2 We can see that x is proportional to CQ=n.