McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
5. Completing the Square
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Exercise 57 Page 261

Practice makes perfect
a

Let's follow each step of the instructions. We start with a square and the midpoint of CD.

Next we draw the arc and the extension of CD. Then we find the intersection point Q.

Finally, we extend AB and draw a perpendicular from Q to DQ to construct the rectangle ARQD.

b

We are given that AD=x, and we know that ABCD is a square and ARQD is a rectangle. This means that we have several congruent segments on the figure all with measure x. Let's mark these on the figure.

We are also given that CQ=1. Let's express the length of the segments involved in the given equation in terms of x. DQ&=x+1 AD&=x QR&=x CQ&=1Let's substitute these expressions and rearrange the resulting equation.

DQ/AD=QR/CQ
x+1/x=x/1
â–¼
Rearrange equation
x+1/x=x
x+1=x^2
1=x^2-x
x^2-x=1

We are asked to use the method of completing the square to solve this equation. This method involves creating a complete square on the left hand side of the equation by adding the square of half the coefficient of the linear term to each side. x^2+ bx=d ⇕ x^2+ bx+(b/2)^2=d+(b/2)^2 ⇕ (x+b/2)^2=d+(b/2)^2 In our case b= -1, so we add ( -12)^2= 14 to each side.

x^2-x=1
x^2-x+ 1/4=1+ 1/4
(x-1/2)^2=1+1/4
(x-1/2)^2=5/4

We can now use the Square Root Property to finish solving the equation.

(x-1/2)^2=5/4
x-1/2=±sqrt(5/4)
x=1/2±sqrt(5/4)
â–¼
Simplify right-hand side
x=1/2±sqrt(5)/2
x=1±sqrt(5)/2

Since x represents a length, it is certainly not negative. x=1+sqrt(5)/2

c

We can use the method in Part B to find x for different values of CQ.

CQ Equation Rearranged Equation Completed Square Positive Solution
1 x+1/x=x/1 x^2-x=1 (x-1/2)^2=5/4 x=1+sqrt(5)/2
2 x+2/x=x/2 x^2-2x=4 (x-1)^2=5 x=1+sqrt(5)
3 x+3/x=x/3 x^2-3x=9 (x-3/2)^2=45/4 x=3+3sqrt(5)/2
4 x+4/x=x/4 x^2-4x=16 (x-2)^2=20 x=2+2sqrt(5)
d

To find a pattern, let's rewrite all values of x as a fraction with the common denominator 2.

CQ x Fraction Form
1 1+sqrt(5)/2 1+sqrt(5)/2
2 1+sqrt(5) 2+2sqrt(5)/2
3 3+3sqrt(5)/2 3+3sqrt(5)/2
4 2+2sqrt(5) 4+4sqrt(5)/2

From this table, we can form a conjecture. IfCQ=n,thenx=n+nsqrt(5)/2=n*1+sqrt(5)/2 We can see that x is proportional to CQ=n.