McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
2. Solving Systems of Inequalities by Graphing
Continue to next subchapter

Exercise 62 Page 152

Practice makes perfect
a There were 6 meetings at the beginning and each meeting costs $25. We can find the expenses of 6 meetings by multiplying the cost of each meeting by the number of meetings.
Expenses: 6* 25= 150

The sum of the expenses and the amount of money left in the account will give us the total amount of money in the account at the beginning. Initial Amount: 150+350=500 Now we can write the equation. Let y be the amount of money in the activities account after having x number of meetings.

Verbal Expression Algebraic Expression
Initial amount in the activities account ($) 500
Cost of having x number of meetings ($) 25 x
The amount of money after having x number of meeting is $y. y=500- 25 x
b The sum of the expenses of 6 meetings and the amount of money left in the account will give us the total amount of money in the account at the beginning.

Initial Amount: 150+350=500

c To find the number meeting that can be covered by $500, we will substitute y=0 into the equation in part (a) and solve it for x. Let's do it!
y=500-25x
0=500-25x
25x=500
x=20
After 20 meetings, there will be no money in activities account.