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Begin by graphing the equations. First two equations represent horizontal lines and last two of them are in slope-intercept form.
(3/2,3), (7/2,7), (8,3), (10,7)
Let's examine the given equations. y=3 y=7 y=2x y=2x-13 Equation I and Equation II represent horizontal lines that pass through the points (0,3) and (0,7), respectively. Let's graph the first two equations.
Next, we will graph the third equation. Notice that it is in slope-intercept form. Thus, we can immediately determine its slopes and y-intercepts. Equation III y= 2x+ 0 To graph it, we will first plot its y-intercept and use its slope to find a second point.
Now we have two points, we can draw a line.
The last equation is also in slope-intercept form, so it can be graphed proceeding in the same way. Equation IV y= 2x -13 Let's graph it!
| Vertex | y-coordinate | Substitution | x-coordinate | Point |
|---|---|---|---|---|
| I | 3 | 3=2x | 3/2 | (3/2,3) |
| II | 7 | 7=2x | 7/2 | (7/2,7) |
| III | 3 | 3=2x-13 | 8 | (8,3) |
| IV | 7 | 7=2x-13 | 10 | (10,7) |