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Graph the given system and determine the vertices of the overlapping region.
Graph:
Vertices: (3,5), (2,- 10), (- 4,4)
Our first step in finding the vertices is to graph the system and determine the overlapping region. Graphing a single inequality involves two main steps.
For this exercise, we need to do this process for each of the inequalities in the system. 3y≥- 7x-16 & (I) 7y≤ x+32 & (II) y≥ 15x-40 & (III) Let's begin!
We can tell a lot of information about the boundary lines from the inequalities given in the system.
Let's find each of these key pieces of information for the inequalities in the system.
| Information | Inequality (I) | Inequality (II) | Inequality (III) |
|---|---|---|---|
| Given Inequality | 3y≥- 7x-16 | 7y≤x+32 | y≥15x-40 |
| Boundary Line Equation | 3y=- 7x-16 | 7y=x+32 | y=15x-40 |
| Solid or Dashed? | ≥ ⇒ Solid | ≤ ⇒ Solid | ≥ ⇒ Solid |
| y= mx+ b | y= -7/3x+( -16/3) | y= 1/7x+ 32/7 | y= 15x+( - 40) |
To draw the first boundary line we will plot the y-intercept and then use the slope to find another point.
We will follow the same process for the second inequality. Let's change the plane dimensions at first, so that it's easier to plot the boundary line.
Now, we will graph this line on the plane with original dimensions. In order to transfer it, we will use the y-intercept and the lattice point, (3,5). Then we can sketch a straight line passing through these points.
One last time we have to follow the process for the third inequality. First, the boundary line.
Finally, we can draw the graphs of the inequalities on the same coordinate plane.
Now that we can see the overlapping region, let's highlight the vertices.
(II): LHS * 7=RHS* 7
(I): Add (II)
(I): Add terms
(I): .LHS /52.=.RHS /52.
(II): .LHS /7.=.RHS /7.
(II): y= 4
(II): Multiply
(II): LHS-32=RHS-32
(II): Rearrange equation