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Graph the given system and determine the vertices of the overlapping region.
Graph:
Vertices: (3.5,8), (- 4,8), (0.5,2)
Our first step in finding the vertices is to graph the system and determine the overlapping region. y≥ 2x+1 & (I) y≤ 8 & (II) 4x+3y≥ 8 & (III)
To graph the inequality, we will have to determine the boundary line first. We can do it by changing the inequality symbol to an equals sign. Inequality:& y≥ 2x+1 Boundary Line:& y=2x+1 Since this equation is in slope-intercept form, we can determine its slope m and y-intercept b to draw the line. Slope-Intercept Form:& y= mx+b Boundary Line:& y= 2x+1 Now that we know the slope and y-intercept, let's use these to draw the boundary line. Notice that the inequality is non-strict, which means that the line will be solid.
The inequality y≤ 8 tells us that all coordinate pairs with a y-coordinate that is less than or equal to 8 will be in the solution set of the inequality. Because the inequality is non-strict, the boundary line will be solid.
Let's draw the graphs of the inequalities on the same coordinate plane.
Now that we can see the overlapping region, let's highlight the vertices.
(II): y= 2x+1
(II): LHS * 3=RHS* 3
(II): LHS+4x=RHS+4x
(II): LHS-3=RHS-3
(II): .LHS /10.=.RHS /10.
(I): x= 0.5
(I): Multiply
(I): Add terms