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Graph the given system and determine the vertices of the overlapping region.
Graph:
Vertices: (2,- 1), (5,8), (- 7,8)
Our first step in finding the vertices is to graph the system and determine the overlapping region. y≥ 3x-7 & (I) y≤ 8 & (II) x+y>1 & (III)
To graph the inequality, we will have to determine the boundary line first. We can do it by changing the inequality symbol to an equals sign. Inequality:& y≥ 3x-7 Boundary Line:& y=3x-7 Since this equation is in slope-intercept form, we can determine its slope m and y-intercept b to draw the line. Slope-Intercept Form:& y= mx+b Boundary Line:& y= 3x+(- 7) Now that we know the slope and y-intercept, let's use these to draw the boundary line. Notice that the inequality is not strict, which means that the line will be solid.
The inequality y≤ 8 tells us that all coordinate pairs with a y-coordinate that is less than or equal to 8 will be in the solution set of the inequality. In this case the boundary line will be horizonatl. It will also be solid, since the inequality is non-strict.
Let's draw the graphs of the inequalities on the same coordinate plane.
Now that we can see the overlapping region, let's highlight the vertices.
(I): y= 3x-7
(I): Add terms
(I): LHS+7=RHS+7
(I): .LHS /4.=.RHS /4.
(II): x= 2
(II): Multiply
(II): Subtract term