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Graph the given system and determine the vertices of the overlapping region.
Graph:
Vertices: (0,0), (0,2), (4,0)
Our first step in finding the vertices is to graph the system and determine the overlapping region. x≥ 0 & (I) y≥ 0 & (II) x+2y<4 & (III)
The inequality x≥ 0 tells us that all coordinate pairs with an x-coordinate that is greater than or equal to 0 will be in the solution set of the inequality. Thus, the boundary line will be vertical. Note that the inequality is non-strict, which means that the line will be solid.
The inequality y≥ 0 tells us that all coordinate pairs with a y-coordinate that is greater than or equal to 0 will be in the solution set of the inequality. In this case the boundary line will be horizontal. It will also be solid, since the inequality is non-strict.
LHS-x=RHS-x
.LHS /2.=.RHS /2.
Put minus sign in front of fraction
a/b=1/b* a
Let's draw the graphs of the inequalities on the same coordinate plane.
Now that we can see the overlapping region, let's highlight the vertices.
Looking at the graph, we can identify the vertices. (0,0), (0,2), (4,0)