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Start by finding a simple geometrical shape to enclose the required area.
Example System:
y≤ - 2 y≥ - 7 x ≥ 3 x ≤ 7
We need our system of inequalities to lie on the fourth quadrant. Let's start by reviewing the quadrants. The coordinate plane is divided into four equal quarters called quadrants. The first quadrant is the one where x and y are positive, and the numbers increase counterclockwise.
Notice that the quadrant we are interested in is that where x takes positive values and y takes negative values.
One of the vertical lines would have to pass through x=3 and another one through x=7. The horizontal lines will pass through y = -2 and y = - 7. Since we will be using vertical and horizontal lines , the equations for them will be of the same form. This is x =3, x =7, y=-2 and y=-7, respectively.
Finally, to contain the area of the rectangle we need the inequality related to y=- 2 to be shaded downwards. We can use y ≤ - 2. Similarly, we want to shade upwards from the line y= - 7, so we can use y ≥ - 7. Finally, we can use x ≥ 3 to shade to the right of the line x=3, and x ≤ 7 to shade to the left of the line x=7.
Our solution is the system of inequalities shown below. y≤ - 2 y≥ - 7 x ≥ 3 x ≤ 7 Notice that this is only an example solution, as there are infinitely many ways to define a system of inequalities with the conditions required by this exercise. For example, we could have used another figure at first, or just different dimensions for the rectangle.