Sign In
To graph f(x)=x^2, make a table of values. By substituting several points for x into the function, you can have an idea about the shape of the graph.
Use the Slope Formula to complete the table.
Look at the table that you completed in Part B. How does the slope change?
Graph:
Table:
| x | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|---|
| f(x) | 16 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 |
| slope | -7 | -5 | -3 | -1 | 1 | 3 | 5 | 7 |
See solution.
To graph f(x)=x^2, we will make a table of values. By substituting several points for x into the function, we can have an idea about the shape of the graph. Let's start!
| x | f(x)=x^2 | f(x) |
|---|---|---|
| -3 | f( -3)=( -3)^2 | 9 |
| -2 | f( -2)=( -2)^2 | 4 |
| -1 | f( -1)=( -1)^2 | 1 |
| 0 | f( 0)=( 0)^2 | 0 |
| 1 | f( 1)=( 1)^2 | 1 |
| 2 | f( 2)=( 2)^2 | 4 |
| 3 | f( 3)=( 3)^2 | 9 |
Let's first complete the second row, the values of f(x). To do that, we can get help from the table in Part A.
| x | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|---|
| f(x) | 16 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 |
| slope | -7 |
Let's consider how we find the slope. To find the slope, we divide the change in y by the change in x.
| Consecutive Points | m=y_2-y_1/x_2-x_1 | Slope |
|---|---|---|
| (-4,16)-(-3,9) | m=9-16/-3-(-4) | -7 |
| (-3,9)-(-2,4) | m=4-9/-2-(-3) | -5 |
| (-2,4)-(-1,1) | m=1-4/-1-(-2) | -3 |
| (-1,1)-(0,0) | m=0-1/0-(-1) | -1 |
| (0,0)-(1,1) | m=1-0/1-0 | 1 |
| (1,1)-(2,4) | m=4-1/2-1 | 3 |
| (2,4)-(3,9) | m=9-4/3-2 | 5 |
| (3,9)-(4,16) | m=16-9/4-3 | 7 |
Finally, we can complete the table by looking at the slope table.
| x | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|---|
| f(x) | 16 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 |
| slope | -7 | -5 | -3 | -1 | 1 | 3 | 5 | 7 |
We can say that the rate of change is not constant. It decreases as x approaches 0 and then increases as x approaches infinity.