McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
Mid-Chapter Quiz
Continue to next subchapter

Exercise 23 Page 892

Use the fact that cot θ = 1tan θ and rewrite 75^(∘) as 120^(∘)-45^(∘). Then, use the Difference of Angles Identity for a tangent function.

2-sqrt(3)

Practice makes perfect

The cotangent of an angle is defined as the quotient of 1 and the tangent of the angle. Using this fact, we can rewrite our expression. cot 75^(∘) = 1/tan 75^(∘) Let's recall the values of the three main trigonometric functions for the most important angles.

Trigonometric Values for Special Angles
Sine Cosine Tangent
sin 0^(∘)=0 cos 0^(∘)=1 tan 0^(∘)=0
sin 30^(∘)=1/2 cos 30^(∘)=sqrt(3)/2 tan 30^(∘)=sqrt(3)/3
sin 45^(∘)=sqrt(2)/2 cos 45^(∘)=sqrt(2)/2 tan 45^(∘)=1
sin 60^(∘)=sqrt(3)/2 cos 60^(∘)=1/2 tan 60^(∘)=sqrt(3)
sin 90^(∘) = 1 cos 90^(∘) = 0 -
sin 120^(∘)= sqrt(3)/2 cos 120^(∘)= - 1/2 tan 120^(∘)= - sqrt(3)
sin 135^(∘)= sqrt(2)/2 cos 135^(∘)= - sqrt(2)/2 tan 135^(∘)= - 1
sin 150^(∘)= 1/2 cos 150^(∘)= - sqrt(3)/2 tan 150^(∘)= - sqrt(3)/3
sin 180^(∘)= 0 cos 180^(∘)= - 1 tan 180^(∘)= 0
sin 210^(∘)= - 1/2 cos 210^(∘)= - sqrt(3)/2 tan 210^(∘)= sqrt(3)/3
sin 240^(∘)= - sqrt(3)/2 cos 240^(∘)= - 1/2 tan 240^(∘)= sqrt(3)
sin 270^(∘)= - 1 cos 270^(∘)= 0 -
sin 300^(∘)= - sqrt(3)/2 cos 300^(∘)= 1/2 tan 300^(∘)= - sqrt(3)
sin 330^(∘) = - 1/2 cos 330^(∘) = sqrt(3)/2 tan 330^(∘) = - sqrt(3)/3
sin 360^(∘)= 0 cos 360^(∘)= 1 tan 360^(∘)= 0
Be aware that 75^(∘) is the difference of 120 ^(∘) and 45^(∘). Therefore, we can rewrite our last expression as 1 over the tangent of a difference. 1/tan 75^(∘)=1/tan (120^(∘)-45^(∘)) We can use the Difference of Angles Identity for a tangent function to find the exact value of the denominator. Then we can calculate its reciprocal. tan ( A- B)=tan A-tan B/1+tan A tan B ⇓ tan ( 120^(∘)- 45^(∘))=tan 120^(∘)-tan 45^(∘)/1+tan 120^(∘) tan 45^(∘) From the table we know that tan 120^(∘)= - sqrt(3) and that tan 45^(∘)= 1. Let's substitute these values into our expression and simplify.

tan 120^(∘)-tan 45^(∘)/1+tan 120^(∘) tan 45^(∘)
- sqrt(3)- 1/1+( - sqrt(3)) 1
â–¼
Simplify
- sqrt(3)-1/1+(- sqrt(3))
- sqrt(3)-1/1- sqrt(3)

We found that the value of tan (120^(∘)-45^(∘)), and therefore the value of tan 75^(∘), is - sqrt(3)-11-sqrt(3). Let's now find its reciprocal. To do so, we switch the numerator and the denominator. ccc Expression & & Reciprocal [0.8em] - sqrt(3)-1/1-sqrt(3) & & 1-sqrt(3)/- sqrt(3)-1 Finally, let's simplify the reciprocal to obtain the value of 1tan 75^(∘). We will need to rationalize the denominator of the expression. Remember, 1tan 75^(∘) is the same as the value of cot 75^(∘) (the original expression).

cot 75^(∘)=1- sqrt(3)/- sqrt(3)-1
â–¼
Simplify right-hand side
cot 75^(∘)=1- sqrt(3)/- sqrt(3)-1 * 1
cot 75^(∘)=1- sqrt(3)/- sqrt(3)-1 * sqrt(3)-1/sqrt(3)-1
cot 75^(∘)=(1-sqrt(3))(sqrt(3)-1)/(- sqrt(3)-1)(sqrt(3)-1)
cot 75^(∘)=1(sqrt(3)-1)-sqrt(3)(sqrt(3)-1)/- sqrt(3)(sqrt(3)-1)-1(sqrt(3)-1)
cot 75^(∘)=sqrt(3)-1-(sqrt(3))^2+sqrt(3)/- (sqrt(3))^2+sqrt(3)-sqrt(3)+1
cot 75^(∘)=sqrt(3)-1-3+sqrt(3)/- 3+sqrt(3)-sqrt(3)+1
cot 75^(∘)=2sqrt(3)-4/- 2
cot 75^(∘)=- 2sqrt(3)-4/2
cot 75^(∘)=- (2sqrt(3)/2-4/2)
cot 75^(∘)=- (2sqrt(3)/2-4/2)
cot 75^(∘)=- (sqrt(3)-2)
cot 75^(∘)=- sqrt(3)+2
cot 75^(∘)=2-sqrt(3)

Extra

Summarizing Our Steps
In summary, we took the following steps to simplify the given expression.

Property Used Equivalency Found
Definition of Cotangent cot 75^(∘) = 1/tan 75^(∘)
Substitution Property of Equality 1/tan 75^(∘) = 1/tan ( 120^(∘)- 45^(∘))
Difference of Angles Identity tan (120^(∘)- 45^(∘)) = tan 120^(∘)-tan 45^(∘)/1+tan 120^(∘) tan 45^(∘)
Values of Tangent tan 120^(∘)-tan 45^(∘)/1+tan 120^(∘) tan 45^(∘) = - sqrt(3)-1/1-sqrt(3)
Reciprocal Fractions 1/tan ( 120^(∘)- 45^(∘)) = 1- sqrt(3)/- sqrt(3)-1
Simplification 1- sqrt(3)/- sqrt(3)-1 = 2-sqrt(3)
Transitive Property cot 75^(∘) = 2-sqrt(3)