McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
3. Probability Distributions
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Exercise 13 Page 748

Practice makes perfect

a

Let's look at the given table.

Distribution of Prices
Prize no prize $ 20 $ 10 $ 5
Probability 0.84 0.01 0.05 0.10

We can make a bar graph of the probability distribution using the information from the table. Each bar will represent a prize, and the bar's height will be proportional to the probability of getting the prize. Here we go!

b

The expected value of a discrete random variable X is the weighted sum of the values of the variable. In our case, the values of the random variables are the prizes of the raffle.

E(X)= ∑ [X* P(X)]In other words, it is what you get if you add up all products of the possible prizes and their corresponding probabilities. Now, let's use the given table to find the products.

Distribution of Prices
Prize, X No prize =$0 $ 20 $ 10 $ 5
Probability, P(X) 0.84 0.01 0.05 0.10
X* P(X) $0*0.84=$0 $20* 0.01=$0.20 $10*0.05=$ 0.50 $5* 0.10=$0.50

Finally, we can calculate the expected value by summing all values from the the third row. Let's do it! E(X)= $0+$0.20+$0.50+ $0.50+$0.50 =$1.20 The expected value, which is what you expect to win on average, is $1.20.

c

In Part B we found that the expected value — which is what a participant of the raffle can expect to gain — is $1.20. Since the price ticket is $1, which is lower than the expected value, it is worth it to participate in the raffle. However, it is not worth it to host the raffle.