Sometimes, when working with math, the exercises are not well defined. Since the following phrase is not preceded by an
exactly or an
at least and because it does not specify the number of men, it could take on multiple meanings. 7of the committee will be women
Other than the previous interpretation and answer, it is possible to have 7, 8, 9, or 10 of the committee be women and still say there are 7 women on the committee. To find the probability we can use the terms of the binomial from where we started above to the end.
∑_(k=7)^(10)10!/k!(10-k)!m^(10-k)w^k
10!/7!(10-7)!m^(10-7)w^7 + 10!/8!(10-8)!m^(10-8)w^8f + 10!/9!(10-9)!m^(10-9)w^9 + 10!/10!(10-10)!m^(10-10)w^(10)
10!/7!*3!m^3w^7 + 10!/8!*2!m^2w^8f + 10!/9!*1!m^1w^9 + 10!/10!*0!m^0w^(10)
10*9*8*7!/7!*3*2*1m^3w^7 + 10*9*8!/8!*2*1m^2w^8f + 10* 9!/9!(1)m^1w^9 + 10!/10!(1)m^0w^(10)
120m^3w^7 + 45m^2w^8 + 10m^1w^9 + m^0w^10
120m^3w^7 + 45m^2w^8 + 10mw^9 + w^10
Now, from the other solution, we know the denominator is 1024.
120/1024 + 45/1024 + 10/1024 +1/1024
176/1024
11/64
To have
at least 7 women on the committee, the probability is 1164.