McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
6. The Binomial Theorem
Continue to next subchapter

Exercise 21 Page 702

Use the specific term of the binomial expansion of (m+w)^(10) when the exponent of w is 7.

15/128

Practice makes perfect
When there are two possible designations for a group, we can use binomial expansion to find probability. Let's let m represent the men and w represent the women. Since there are ten people on the committee, we can use (m+w)^(10). (m+w)^(10) = ∑_(k=0)^(10)10!/k!(10-k)!m^(10-k)w^kWe need the term when the exponent of w is 7 because we need to know when there are 7 women on the committee. Let's look at the term of the summation when k=7 and evaluate it.
10!/k!(10-k)!m^(10-k)w^k
10!/7!(10- 7)!m^(10- 7)w^7
Simplify
10!/7!*3!m^3w^7

Write as a product

10*9*8*7!/7!*3*2*1m^3w^7
10*9*8/3*2*1m^3w^7
720/6m^3w^7
120m^3w^7
Since the selection of men or women is equally likely, we can substitute m= 12 and w= 12 to find the probability.
120m^3w^7
120( 1/2)^3( 1/2)^7
Evaluate
120(1/8)(1/128)
120 (1/1024)
120/1024
15/128
Therefore, the probability that 7 members will be women is 15128.

Alternative Solution

Alternative Interpretation
Sometimes, when working with math, the exercises are not well defined. Since the following phrase is not preceded by an exactly or an at least and because it does not specify the number of men, it could take on multiple meanings. 7of the committee will be women Other than the previous interpretation and answer, it is possible to have 7, 8, 9, or 10 of the committee be women and still say there are 7 women on the committee. To find the probability we can use the terms of the binomial from where we started above to the end.
∑_(k=7)^(10)10!/k!(10-k)!m^(10-k)w^k
Evaluate
10!/7!(10-7)!m^(10-7)w^7 + 10!/8!(10-8)!m^(10-8)w^8f + 10!/9!(10-9)!m^(10-9)w^9 + 10!/10!(10-10)!m^(10-10)w^(10)
10!/7!*3!m^3w^7 + 10!/8!*2!m^2w^8f + 10!/9!*1!m^1w^9 + 10!/10!*0!m^0w^(10)

Write as a product

10*9*8*7!/7!*3*2*1m^3w^7 + 10*9*8!/8!*2*1m^2w^8f + 10* 9!/9!(1)m^1w^9 + 10!/10!(1)m^0w^(10)
120m^3w^7 + 45m^2w^8 + 10m^1w^9 + m^0w^10

Simplify power

120m^3w^7 + 45m^2w^8 + 10mw^9 + w^10
Now, from the other solution, we know the denominator is 1024.
120/1024 + 45/1024 + 10/1024 +1/1024
176/1024
11/64
To have at least 7 women on the committee, the probability is 1164.