McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
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Exercise 46 Page 713

Find the first term and the common ratio of a geometric sequence.

300ft

Practice makes perfect
Let a_n be the total vertical distance that the rubber ball travels after the nth bounce, but only going down. Since the ball is dropped from 60 feet, a_1= 60. After each bounce the ball can bounce back to 23 of the previous height, so a_n is a geometric sequence and its common ratio is r= 23. a_n - geometric sequence a_1= 60, r= 2/3 The total vertical distance that ball travels going down is represented by the following sum of an infinite geometric series. 60+ 60( 2/3)+ 60( 2/3)^2+ 60( 2/3)^3+... Since the common ratio r= 23 satisfies the inequalities - 1< r<1, we can use the formula for the sum of an infinite geometric series. S=a_1/1- r Let's substitute values for a_1 and r. Then, we will find S.
S=a_1/1- r
S=60/1- 23
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Simplify right-hand side
S=60/33- 23
S=60/13
S=60* 3/1
S=180/1
S= 180
The total vertical distance that the ball travels only going down is S_(↓)= 180 ft. Next, we will calculate the total vertical distance that the ball travels only going up, S_(↑). Notice that S_(↓) and S_(↑) differ only in the first fall of the ball, a_1= 60.
S_(↑)= S_(↓)- a_1
S_(↑)= 180- 60
S_(↑)= 120
Since S_(↓)= 600 feet and S_(↑)= 570 feet, the total vertical distance that the ball travels is S_(↓)+ S_(↑)= 180+ 120=300 feet.