a_1&=16
a_(n+1)&=a_n+4
To do so, we will use a table. To find a_2, we will substitute 1 for n in the above formula. To find a_3, we will substitute 2 for n, and so on.
n
a_(n+1)=a_n+4
a_n+4
a_(n+1)
-
a_1= 16
-
-
1
a_(1+1)=a_1+4 ⇕ a_2=a_1+4
a_2= a_1+4 ⇓ a_2= 16+4
a_2= 20
2
a_(2+1)=a_2+4 ⇕ a_3=a_2+4
a_3= a_2+4 ⇓ a_3= 20+4
a_3= 24
3
a_(3+1)=a_3+4 ⇕ a_4=a_3+4
a_4= a_3+4 ⇓ a_4= 24+4
a_4= 28
4
a_(4+1)=a_4+4 ⇕ a_5=a_4+4
a_5= a_4+4 ⇓ a_5= 28+4
a_5= 32
The first five terms of the sequence are 16, 20, 24, 28, and 32.
