McGraw Hill Glencoe Algebra 1 Texas, 2016
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McGraw Hill Glencoe Algebra 1 Texas, 2016 View details
3. Simplifying Rational Expressions
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Exercise 1 Page 693

Consider the given rational expression. 8/x^2-16 To identify the excluded values, we need to remember that the denominator cannot be equal to 0 because division by 0 is not defined. This means we need exclude the values of x that would make the denominator equal to 0. x^2-16=0 One way of solving such quadratic equations is through factoring. We can use the Difference of Squares Formula for that.
x^2-16=0
x^2-4^2=0
(x+4)(x-4)=0
Once the expression is written in factored form, we can apply the Zero Product Property to find the solutions to the equation.
(x+4)(x-4)=0
lcx+4=0 & (I) x-4=0 & (II)
lx=- 4 x-4=0
lx=- 4 x=4
These two values make the denominator equal to 0. Therefore, the excluded values are - 4 and 4.