McGraw Hill Glencoe Algebra 1, 2017
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McGraw Hill Glencoe Algebra 1, 2017 View details
4. Solving Compound Inequalities
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Exercise 1 Page 312

Since the word between the inequalities is and, we are looking for where the solution sets intersect.

Solution Set: 12≤ p≤16
Graph:

Practice makes perfect

To solve the compound inequality, we will solve each of the inequalities separately and then graph them together. The intersection of these solution sets is the solution set for the compound inequality.

First Inequality

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when we divide or multiply by a negative number, we must reverse the inequality sign.
4≤ p-8
12≤ p
This above tells us that all values greater than or equal to 12 will satisfy the inequality.

Note that the point on 12 is closed because it is included in the solution set.

Second Inequality

Again, we will solve the inequality by isolating the variable.
p-14≤2
p≤16
The second inequality is satisfied for all values of p that are less than or equal to 16.

Note that the point on 16 is closed because it is included in the solution set.

Compound Inequality

The solution to the compound inequality is the intersection of the solution sets. First Solution Set: 12≤ p& Second Solution Set: p&≤ 16 Intersecting Solution Set: 12≤ p& ≤ 16 Finally, we will graph the solution set to the compound inequality on a number line.